How to find electric potential given only velocity

Click For Summary
SUMMARY

The discussion focuses on calculating the change in electric potential (ΔV) given a velocity of 4.8×105 m/s. The relevant equation is ΔV = Vf - Vi = -W/q, where W represents work done and q is charge. Participants emphasize the need for additional context beyond velocity alone, highlighting the relationship between electric potential difference and the kinetic energy of charged particles, specifically electrons. The kinetic energy formula KE = 1/2mv2 and the energy unit electron Volts (eV) are also discussed as critical components in solving the problem.

PREREQUISITES
  • Understanding of electric potential and its relationship to work and charge
  • Familiarity with kinetic energy calculations, specifically KE = 1/2mv2
  • Knowledge of energy units, particularly electron Volts (eV)
  • Basic principles of electric fields and forces on charged particles
NEXT STEPS
  • Study the relationship between electric potential and kinetic energy in charged particles
  • Learn how to convert between kinetic energy and electric potential energy
  • Explore the implications of electric fields on particle motion
  • Investigate the role of charge in determining electric potential differences
USEFUL FOR

Students in physics, particularly those studying electromagnetism, as well as educators and anyone seeking to understand the relationship between velocity and electric potential in charged particles.

jlmccart03
Messages
175
Reaction score
9

Homework Statement


Given v = v=4.8×105m/s find the change in electric potential.

Homework Equations


ΔV = Vf-Vi = -W/q

The Attempt at a Solution


I really don't know any other formula that has the use of velocity to find ΔV. So how does velocity end up into the mix in finding ΔV?
 
Physics news on Phys.org
There has to be more to the given problem than what you've written. A velocity alone says nothing about what the scenario is. What is the complete problem statement?
 
gneill said:
There has to be more to the given problem than what you've written. A velocity alone says nothing about what the scenario is. What is the complete problem statement?
Here is a picture.
upload_2017-2-14_19-6-10.png
 
jlmccart03 said:

Homework Statement


Given v = v=4.8×105m/s find the change in electric potential.

Homework Equations


ΔV = Vf-Vi = -W/q

The Attempt at a Solution


I really don't know any other formula that has the use of velocity to find ΔV. So how does velocity end up into the mix in finding ΔV?
Whelp, that post didn't go so well.

It's good to know that v=v, that's always a good start... :smile:

A potential difference produces an accelerating force on a charged particle, not just a "velocity" in isolation. There needs to be a lot more to this question that you haven't posted so far?

EDIT -- gneill beat me to it (again)...
 
  • Like
Likes   Reactions: gneill
jlmccart03 said:
Here is a picture.View attachment 113222
Oh, that's a lot easier. What do you know about the units of energy "eV" (electron Volts) and how you express the kinetic energy of a moving electron...?
 
berkeman said:
Oh, that's a lot easier. What do you know about the units of energy "eV" (electron Volts) and how you express the kinetic energy of a moving electron...?
Well units of energy eV is 1.6*10^-19 J and KE = 1/2mv^2 for an electron.
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
2K
Replies
4
Views
6K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 4 ·
Replies
4
Views
6K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 22 ·
Replies
22
Views
4K
  • · Replies 2 ·
Replies
2
Views
3K