Strength of electric field given potential difference

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Homework Help Overview

The discussion revolves around determining the strength of the electric field between two parallel conducting plates, given a specific potential difference and separation distance. The subject area is primarily focused on electrostatics and electric fields.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster expresses uncertainty about how to begin solving the problem and reflects on their struggles with the course material. Some participants later confirm the use of the equation E = ΔV/d for this scenario and discuss unit conversions related to electric field strength.

Discussion Status

There is a progression in the discussion where the original poster initially seeks help but later indicates they have arrived at a solution. Participants provide supportive feedback and engage in clarifying the units of measurement for electric fields.

Contextual Notes

The original poster mentions a potential struggle with the course in general, which may indicate a broader context of learning challenges. There is also a note about the use of different units (N/C vs. V/m) that reflects a common point of confusion in the subject matter.

Mickael14

Homework Statement


What is the strength of the electric field between two parallel conducting plates separated by 1.00 cm and having a potential difference (voltage) between them of 1.50×104 V?

Homework Equations


ΔV = qΔU
ΔV = -∫E⋅dl
E = kq/r2

The Attempt at a Solution


I am not sure where to start. I am looking at the equations available, and I can't seem to figure out where to go from here. I have been struggling with this course in general. If someone could help me out with this, I would really appreciate it.
 
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Never mind, I got it. :)
I forgot that qΔV = W and W = Fd, then I can use the substitution F = qE to get qEd = qΔV
So,
E = ΔV/d
E = (1.50x104)/(.01) = 1.5x106 N/C
 
Mickael14 said:
E = ΔV/d
Yes, that is the correct equation for this simple geometry. Good work, and Welcome to the PF. :smile:
 
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Mickael14 said:
E = (1.50x104)/(.01) = 1.5x106 N/C
BTW, the usual units for E-field are V/m. Can you show the equivalence between V/m and N/C?
 
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berkeman said:
BTW, the usual units for E-field are V/m. Can you show the equivalence between V/m and N/C?
Oh, sorry I put in in N/C because that is what we had been using. Forgot to change.
 

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