Strength of electric field given potential difference

[Mickael14]

Homework Statement

What is the strength of the electric field between two parallel conducting plates separated by 1.00 cm and having a potential difference (voltage) between them of 1.50×104 V?

Homework Equations

ΔV = qΔU
ΔV = -∫E⋅dl
E = kq/r²

The Attempt at a Solution

I am not sure where to start. I am looking at the equations available, and I can't seem to figure out where to go from here. I have been struggling with this course in general. If someone could help me out with this, I would really appreciate it.

 

[Mickael14]

Never mind, I got it. :)
I forgot that qΔV = W and W = Fd, then I can use the substitution F = qE to get qEd = qΔV
So,
E = ΔV/d
E = (1.50x10⁴)/(.01) = 1.5x10⁶ N/C

 

[berkeman]

E = ΔV/d

Yes, that is the correct equation for this simple geometry. Good work, and Welcome to the PF.

 

[berkeman]

E = (1.50x104)/(.01) = 1.5x106 N/C

BTW, the usual units for E-field are V/m. Can you show the equivalence between V/m and N/C?

 

[Mickael14]

BTW, the usual units for E-field are V/m. Can you show the equivalence between V/m and N/C?

Oh, sorry I put in in N/C because that is what we had been using. Forgot to change.