How to find electric potential given only velocity

Click For Summary

Homework Help Overview

The discussion revolves around finding the change in electric potential (ΔV) given a velocity of 4.8×105 m/s. Participants are exploring how velocity relates to electric potential in the context of charged particles and energy concepts.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants question the completeness of the problem statement, noting that velocity alone does not provide sufficient context for determining ΔV. There are inquiries about the scenario and additional information that may be necessary.

Discussion Status

Some participants have provided guidance by suggesting that the relationship between potential difference and the motion of charged particles needs further clarification. There is an acknowledgment that more context is required to properly address the problem.

Contextual Notes

There are indications that the original poster may not have included all relevant details of the problem, which could affect the interpretation and approach to finding ΔV.

jlmccart03
Messages
175
Reaction score
9

Homework Statement


Given v = v=4.8×105m/s find the change in electric potential.

Homework Equations


ΔV = Vf-Vi = -W/q

The Attempt at a Solution


I really don't know any other formula that has the use of velocity to find ΔV. So how does velocity end up into the mix in finding ΔV?
 
Physics news on Phys.org
There has to be more to the given problem than what you've written. A velocity alone says nothing about what the scenario is. What is the complete problem statement?
 
gneill said:
There has to be more to the given problem than what you've written. A velocity alone says nothing about what the scenario is. What is the complete problem statement?
Here is a picture.
upload_2017-2-14_19-6-10.png
 
jlmccart03 said:

Homework Statement


Given v = v=4.8×105m/s find the change in electric potential.

Homework Equations


ΔV = Vf-Vi = -W/q

The Attempt at a Solution


I really don't know any other formula that has the use of velocity to find ΔV. So how does velocity end up into the mix in finding ΔV?
Whelp, that post didn't go so well.

It's good to know that v=v, that's always a good start... :smile:

A potential difference produces an accelerating force on a charged particle, not just a "velocity" in isolation. There needs to be a lot more to this question that you haven't posted so far?

EDIT -- gneill beat me to it (again)...
 
  • Like
Likes   Reactions: gneill
jlmccart03 said:
Here is a picture.View attachment 113222
Oh, that's a lot easier. What do you know about the units of energy "eV" (electron Volts) and how you express the kinetic energy of a moving electron...?
 
berkeman said:
Oh, that's a lot easier. What do you know about the units of energy "eV" (electron Volts) and how you express the kinetic energy of a moving electron...?
Well units of energy eV is 1.6*10^-19 J and KE = 1/2mv^2 for an electron.
 

Similar threads

Accelerated Electron and its Potential Energy
  • · Replies 5 ·
Replies
5
Views
2K
Electron brought to rest by the E-field, potential difference question
  • · Replies 4 ·
Replies
4
Views
6K
Understand Electric Potential Energy, Difference & Potential
  • · Replies 2 ·
Replies
2
Views
2K
The work done by the electric field between two plates
  • · Replies 3 ·
Replies
3
Views
2K
Electric Field and Potential Scenario
  • · Replies 1 ·
Replies
1
Views
1K
Strength of electric field given potential difference
  • · Replies 4 ·
Replies
4
Views
6K
Potential and Electric Field near a Charged CD Disk
  • · Replies 2 ·
Replies
2
Views
2K
How come electric potentials have different signs?
  • · Replies 5 ·
Replies
5
Views
2K
Why Is Work Positive When Done Against the Electric Field?
  • · Replies 22 ·
Replies
22
Views
4K
Electric Fields and Electric Potential
  • · Replies 2 ·
Replies
2
Views
3K