How to find forces acting on object on a slope?

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SUMMARY

The discussion centers on resolving forces acting on an object resting on a slope at an angle σ. The key equations derived include Ft = G sin σ and Fn = G cos σ, where G represents the gravitational force. Participants emphasize the importance of drawing a triangle of forces to visualize the relationship between the gravitational force and its components. The confusion arises from the application of trigonometric functions Soh Cah Toa, which are essential for understanding the relationships between the angles and sides of the triangle formed by the forces.

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  • Understanding of basic trigonometry, specifically sine and cosine functions.
  • Familiarity with Newton's laws of motion and gravitational force.
  • Ability to draw and interpret force diagrams, particularly triangles of forces.
  • Knowledge of vector resolution in physics.
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  • Study the application of trigonometric identities in physics problems involving inclined planes.
  • Learn how to construct and analyze free-body diagrams for various physical scenarios.
  • Explore the concept of vector resolution in greater depth, focusing on forces acting at angles.
  • Review examples of problems involving forces on slopes to reinforce understanding of the concepts.
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Students studying physics, particularly those focusing on mechanics and forces, as well as educators looking to clarify concepts related to inclined planes and vector resolution.

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Homework Statement

an object is at rest on a slope at angle of σ

Using trigonometry, solve the forces acting at Ft and Fn

2ezlnqa.jpg

Homework Equations



Soh
Cah
Toa

The Attempt at a Solution



sin σ = G/Ft
sin σ /Ft = G
G/ sin σ = Ft (my final answer)

Book says correct answer is Ft = G sinσFn = ? I wanst even sure how to strat this using σ

The book says the correct answer is Fn = G cosσ

Homework Statement


Homework Equations


The Attempt at a Solution

 
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The force G can be resolved into 2 components: one which is normal to the slope (the exact opposite to Fn), and one which is parallel to the slope (the exact opposite to Ft).

Draw the triangle of forces showing how G equals the vector sum of these two forces.
 
edited...I'll be back
 
Last edited:
Thanks NascentOxygen. Unfortunately I don't quite get why the answers are what they are. I have drawn myself a new triangle which shows the two vector forces but I still don't understand where the answers have come from.

Especially Fn = G cosσ. I thought cos in basic terms meant adjacent/hypothenuse . So if the sloped line is the hypothenuse and the bottom line is the adjacent once I draw the line which is exact opposite to Fn I now no longer have a right angle triangle...arghh! I'm just so confused...
 
Show your diagrams.
 
here is my latest diagram
2yw8ygz.jpg


I'm now starting to think Soh Cah Toa isn't actually relevant there ?

Fn = G cosσ Ft = Gσ

I'm unsure where these two formulas/equations have come from and why Soh Cah Toa isn't relevant here...

I must be missing something fundamental
 
urbano said:
here is my latest diagram
It's the triangle beneath the object which you need to focus on.
redraw it separately, and larger, and label what you know. Its vertical line represents G Newtons.
 
urbano said:
here is my latest diagram
It's the triangle beneath the object which you need to focus on. Redraw it separately, and larger, and label what you know. Its vertical line represents G Newtons.
 

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