How to find height in Projectile Motion?

  • Thread starter SHENGTON
  • Start date
  • #1
6
0
Hello guys!

I need your help regarding Projectile Motion because I kinda novice here. I don't know where to start.

These are the following given:
Vi = 23.2 miles/hour
h = ?
x = 1 km

Here's the situation it looks like, check this image that I created for you to understand.

ProjectTile.jpg


Hope someone can help me with this.

Thanks and God bless. :)

Homework Statement





Homework Equations





The Attempt at a Solution

 

Answers and Replies

  • #2
445
5
For a start you'd need to have an angle of projection, and convert all figures into the same system. The diagram isn't over clear to me, as it seems your plane is pointing away from the projection (but it is early here)
 
  • #3
99
1
Unit are not the same here!!!
You need to find time.
Use these formulae you can get the answer. Don't forget to change same unit here. SI and British Unit!!!
t=x/Vi
h=0.5gt^2
 
  • #4
251
0
remember that the velocity in x direction is constant then you can use the x component velocity to find time by D=VT then solve for height in y direction
 
  • #5
Like seto6 said, the acceleration in X is 0. You can find the time that you will need to resolv the Y equation.
 
  • #6
99
1
Actually, All of us(seto6, proculation and inky) method are the same.
v[0x]=v[x]=v
v[0y]=0

t=x/v=1/(23.2*1.6)=0.0269 hr=96.84 s
h=y=v[0y]t+0.5gt[2]=0+0.5(10)(96.84^2)=46890m=46.89 km
 
Last edited:

Related Threads on How to find height in Projectile Motion?

Replies
1
Views
2K
  • Last Post
Replies
6
Views
9K
  • Last Post
Replies
2
Views
2K
  • Last Post
Replies
5
Views
2K
  • Last Post
Replies
2
Views
1K
  • Last Post
Replies
10
Views
5K
Replies
2
Views
4K
  • Last Post
Replies
3
Views
6K
  • Last Post
Replies
0
Views
1K
  • Last Post
Replies
0
Views
860
Top