How to find KE and PE without mass

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SUMMARY

This discussion addresses the calculation of kinetic energy (KE) and potential energy (PE) for a simple pendulum without knowing the mass. The key takeaway is that when mass is not provided, one can derive symbolic results or use specific values, which are per-unit-mass values. The kinetic energy can be expressed as KE = (1/2) * inertia * omega^2, and potential energy can be represented as PE = g * Δh. By canceling mass terms in equations, one can simplify the analysis to specific energy values.

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I am working on Computational physics homework and it asks to find the kinetic and potential energy of a simple pendulum. My only issue is that i don't know how to solve it without mass.
It gives me :
theta (pendulum angle)
omega (pendulum angular Velocity)
t (time)
length (length of string)
dt (time step)

I was looking at the kinetic energy equation and maybe I need to use Inertia for where KE = (1/2) (inertia)(omega) ? but then how would i find inertia?



Any help would be appreciated.
 
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Hi alex steve, Welcome to Physic Forums

Please be sure to retain and use the formatting template that is provided in the edit window when posting a question in the homework areas of the forums. This is a requirement of the forum rules.

If no mass or moment of inertia are provided then the best you can do is provide a symbolic result, or assume an arbitrary value of mass for the problem.

An alternative is to use "specific" values. A specific value is a per-unit-mass value. For example, one might say that the specific kinetic energy of some object is 20 Joules per kg. If the body turned out to have a mass of 1 kg then it would have a KE of 20 J. If it turned out to be 100 kg, then it would have 2000 J of KE. Specific values are handy in some areas where particular mass values aren't known or don't matter too much to the details of the problem. A case in point might be where one is equating a change in potential energy to a change in kinetic energy. Normally one would write something like ##M g Δh = 1/2 M v^2##. Note that the M's cancel on both sides. So you could just write it as ##g Δh = 1/2 v^2##.

##g Δh## would be the "specific potential energy, and ##v^2/2## would be the specific kinetic energy.
 
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