How to find magnitude of centripetal acceleration and of net force?

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SUMMARY

The discussion focuses on calculating the magnitude of centripetal acceleration and net force for riders on a ferris wheel with a radius of 12 m and a speed of 8 m/s. The centripetal acceleration is determined using the formula v²/r, resulting in a value of 5.33 m/s². For the net force required to produce this acceleration for a rider with a mass of 70 kg, the calculation involves multiplying the centripetal acceleration by the mass, confirming the correct approach to solving the problem.

PREREQUISITES
  • Understanding of centripetal acceleration and its formula (v²/r)
  • Knowledge of Newton's second law (F = ma)
  • Familiarity with net force calculations (Fnet = N - W)
  • Basic algebra skills for manipulating equations
NEXT STEPS
  • Study the effects of varying radius and speed on centripetal acceleration
  • Explore real-world applications of centripetal force in amusement park rides
  • Learn about the relationship between mass and force in circular motion
  • Investigate advanced topics in dynamics, such as angular momentum
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and circular motion, as well as educators looking for practical examples of centripetal acceleration and net force calculations.

starplaya
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Homework Statement


A ferris wheel at a carnival has a radius of 12 m and turns so that the speed of the riders is 8m/s
a) what is the magnitude of the centripetal acceleration of the riders?
b) what is the magnitude of the net force required to produce this centripetal acceleration for a rider with a mass of 70kg?


Homework Equations



Centripetal acceleration = v^2/r
F = ma
Fnet = N - W = m(centripetal acceleration)

The Attempt at a Solution



centripetal acceleration = 8^2/ 12 = 5.33 m/s^2
 
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starplaya said:
centripetal acceleration = 8^2/ 12 = 5.33 m/s^2
Looks good.
 
Doc Al said:
Looks good.

so, 5.33 m/s^2 would be the answer for part A and for part B i just multiply the acceleration by the mass?
 
starplaya said:
so, 5.33 m/s^2 would be the answer for part A and for part B i just multiply the acceleration by the mass?
That's correct.
 
Boy was I over thinking that. Thanks a lot for the clarification
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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