How to find magnitude of Q1 and Q2?

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SUMMARY

The discussion focuses on calculating the magnitudes of two point charges, Q1 and Q2, which are 6 meters apart. The electric field intensity at point A, located midway between the charges, is 5 N/C directed toward Q2, and the electric potential at that point is 45V. The relationship between potential and charge is established using the equation VA = k [(Q1 + Q2)/r], leading to the equation 45 V = 9x109 [(Q1 + Q2)/3]. To solve for Q1 and Q2, participants are advised to derive a second equation based on the electric field intensity.

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Homework Statement


Two point charges, Q1 and Q2 are 6m apart. The electric field intensity a point A, midway between the two charges is 5 N/C directed toward Q2, and the potential at the same point is 45V. Find:
a) the magnitude of Q1
b) the magnitude of Q2



Homework Equations





The Attempt at a Solution



This is what I got so far.
VA = k [(Q1+Q2)/r]
45 V = 9x109 [(Q1+Q2)/3]

Then I'm stuck at what to do next and what to do with E = 5 N/C
 
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s0mebody said:

Homework Statement


Two point charges, Q1 and Q2 are 6m apart. The electric field intensity a point A, midway between the two charges is 5 N/C directed toward Q2, and the potential at the same point is 45V. Find:
a) the magnitude of Q1
b) the magnitude of Q2



Homework Equations





The Attempt at a Solution



This is what I got so far.
VA = k [(Q1+Q2)/r]
45 V = 9x109 [(Q1+Q2)/3]

Then I'm stuck at what to do next and what to do with E = 5 N/C

5 N/C is the field intensity at the same point for which you've written an expression for the potential. You're also given the net field direction there. You'll want to write an expression for the field in terms of Q1, Q2, and their distances from that point. That will give you two equations and two unknowns...
 

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