How to Find Roots of Complex Numbers in Non-Linear Multi-Variable Equations?

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SUMMARY

This discussion focuses on solving non-linear multi-variable equations involving complex numbers, specifically the equations z^6=(64,0) and z^4=(3,4). The real and imaginary components are separated into two distinct equations for each case, leading to complex algebraic manipulations. The user seeks assistance in deriving the roots algebraically without resorting to Euler's formula, highlighting the complexity of the second equation which lacks a straightforward zero equation. The conversation emphasizes the need for algebraic techniques to find solutions for these equations.

PREREQUISITES
  • Understanding of complex numbers and their properties
  • Familiarity with algebraic manipulation of polynomial equations
  • Knowledge of real and imaginary components in complex equations
  • Experience with non-linear multi-variable systems
NEXT STEPS
  • Study algebraic methods for solving non-linear equations
  • Learn about the polar form of complex numbers and its applications
  • Explore techniques for separating real and imaginary components in complex equations
  • Investigate the use of substitution methods in multi-variable systems
USEFUL FOR

Mathematics students, educators, and anyone involved in solving complex algebraic equations, particularly those dealing with non-linear multi-variable systems.

Koolaidbrah
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Homework Statement


1. z^6=(64,0)
2. z^4=(3,4)


Homework Equations


These are expanded out into Real and Imaginary components (treat them separate):
1. REAL (EQ 1) - x^6-15x^4y^2+15x^2y^4-y^6=64
IMAG (EQ 2) - 6x^5y-20x^3y^3+6xy^5=0
From here, you basically solve these for all six roots.
2. REAL (EQ 1) - x^4-6x^2y^2+y^4=3
IMAG (EQ 2) - 4x^3y-4xy^3=4


The Attempt at a Solution


These must be done algebraically, not using Euler angle components (answer would be trivial)

For #1, I have EQ 2 broken down into
3z^2+3v^2=10zv where z=x^2 and v=y^2.
I know the solution is z= 3z and z=3/z, which I can then plug into EQ 1, and all my answers will be given. My algebra is just lacking to get those 2 answers for z.

#2 is a lot more difficult and there is no 'zero equation'. Professor gave us hint to make both sides =12 at the end, subtract them to get an equation with 0; this gives me 3 equations

EQ 2 - xy(x^2-y^2)=1
EQ 1 - x^4+y^4=3(1+2x^2y^2)
EQ 3 (new formed, what I will likely end up using to solve x in terms of y) - x^4-3x^3y-6x^2y^2+3xy^3+y^4=0

My algerbra must be lacking. Not looking for a given answer, but any hints that will help me solve these non-linear multi-variable system of equations
 
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Is there some reason you're avoiding using the polar (complex exponential) form of complex numbers?
 

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