How to find tension in a rope when given the force?

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In a tug of war scenario where each athlete pulls with a force of 200N, the tension in the rope is also 200N, as the forces exerted by both athletes are equal and opposite. If the rope does not move, each athlete must exert a force of 200N against the ground to maintain their position. It is important to consider that the athletes' weights may affect the forces involved, but if their weights are negligible, the forces will align in a single line of action. The discussion emphasizes the relationship between the pulling force and the resulting tension in the rope. Understanding these dynamics is crucial for solving similar physics problems.
Amelina Yoo
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Moved from a technical forum, so homework template missing
Q: In a tug of war between 2 athletes, each pulls on the rope with a force of 200N.

a) What is the tension in the rope?
b) If the rope does not move, what force is each athlete exerting on the ground?

I wrote for both a) and b) 200N, and I am unable to confirm this because my textbook has no answers. I am also not very confident with this question, and am unable to justify my answers. Can someone please explain how to do this question?
 
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Amelina Yoo said:
Q: In a tug of war between 2 athletes, each pulls on the rope with a force of 200N.

a) What is the tension in the rope?
b) If the rope does not move, what force is each athlete exerting on the ground?

I wrote for both a) and b) 200N, and I am unable to confirm this because my textbook has no answers. I am also not very confident with this question, and am unable to justify my answers. Can someone please explain how to do this question?
Your answers are correct, except that in b) I assume the athletes also have some weight.
It sounds like a homework question. If so, it should have been posted in a homework forum.
 
Imagine the athlete on one end of the rope. If the rope had more than 200N tension then the athlete would be pulled toward the rope. So the tension in the rope is the same as the force exerted by each athlete, 200N. Suppose the feet of each athlete were affixed to the ground and that their weights are negligible. Let's look again at one athlete. That athlete is are pulling with a force of 200N, the tension in the rope is 200N, they are pushing toward the rope with their feet at 200N.
 
OldYat47 said:
Suppose the feet of each athlete were affixed to the ground and that their weights are negligible.
You would also need to assume that the athletes are almost flat to the ground.
 
Yes. If the weights are negligible then the forces all have to "line up" in a single line of action.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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