How to find the domain in one dimension

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Homework Help Overview

The discussion revolves around finding the domain of functions defined in higher dimensions, specifically from R² to R³ and R³ to R. The original poster expresses uncertainty about extending their understanding of domains from one-dimensional cases to two and three dimensions.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the nature of the domains for the given functions, with some questioning whether the domain can simply be all real numbers or if it must be more specific. There is also a focus on identifying restrictions based on the function definitions.

Discussion Status

Several participants have provided insights into the nature of the domains, with some clarifying that the domain for the first function is R² and that the second function has a restriction on the values of y and z. The conversation indicates a productive exploration of the topic, with participants refining their understanding of the domain definitions.

Contextual Notes

There is a noted lack of explicit definitions for the domains in the original problem, leading to various interpretations and assumptions being discussed. The participants are navigating these uncertainties while attempting to clarify the requirements for each function's domain.

tomfrank
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Homework Statement


I am trying to find the domain of the following..

R^2 to R^3 of g(x,y) = (x-y,x+y,3*x)
R^3 to R of h(x,y,z) = x/(y+z)

Homework Equations


The Attempt at a Solution



I don't know how to start. I know how to find the domain in one dimension but how do you do it in 2 or 3 dimensions?
Thanks
 
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Your second function is actually R^3->R. Since they didn't tell you what the domain is, you just want to pick the domain of f:A->B to be all of the points in A where the function is defined.
 


so for the first one can just do from (-infinity to infinity) ?

can i just put in any value of x i want to?
 


For the first one, your domain is not just R, the real line; it's the real plane, R2. For the second one, there is a restriction on y and z.
 


tomfrank said:
so for the first one can just do from (-infinity to infinity) ?

can i just put in any value of x i want to?

Basically, yes. But the domain isn't (-infinity,infinity), that's a subset of R. The domain should be a subset of R^2. How about saying it's ALL of R^2?
 


So the first one domain = R^2 the real plane

second one = is y+z not equal to '0'

is that right?
 


Yes, pretty much. You can say it a little nicer as
[tex]\{(x, y, z)\in R^3 | y + z \neq 0\}[/tex].
 


that looks nice thanks
 

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