How to Find the Equation of a Circle with Given Points and Radius?

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To find the equation of a circle that intersects the x-axis at points (-2,0) and (2,0) with a radius of 5, the center of the circle can be determined as (0,h) where h is the y-coordinate. The equation of the circle can be expressed as (x-0)² + (y-h)² = 5². The value of h can be calculated using the relationship between the radius and the distance from the center to the x-axis. This leads to the final equation of the circle being x² + (y-h)² = 25, where h is derived from the radius. The discussion emphasizes the importance of correctly identifying the points and the center for solving the problem.
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Homework Statement



Find the equation of the circle which intersects the x-axis at two points at 2 unit distance from the origin and the radius is 5

Homework Equations


x^2 + y^2 + 2gx + 2fy + c=0

r=(g^2+f^2-c)^1/2


The Attempt at a Solution


I first tried to solve it by assuming that the two points are (2,0) and (2+x,0). The main conundrum is solving for x and also finding out the center of the circle
 
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Hi Dumbledore211! :smile:
Dumbledore211 said:
Find the equation of the circle which intersects the x-axis at two points at 2 unit distance from the origin …

No, they're both at 2 from the origin, so they're x = ±2. :wink:

(and so the centre will … ?)
 
Dumbledore211 said:

Homework Statement



Find the equation of the circle which intersects the x-axis at two points at 2 unit distance from the origin and the radius is 5

Homework Equations


x^2 + y^2 + 2gx + 2fy + c=0
(x-g)^2 + (y-h)^2= r^2


The Attempt at a Solution


I first tried to solve it by assuming that the two points are (2,0) and (2+x,0). The main conundrum is solving for x and also finding out the center of the circle

The two points on the x- axis at 2 unit distance from the origin are (-2,0) and (2,0) . I guess now it should be easy for you :smile:
 
Thank you. It should be fairly easy to solve it using your helpful info
 

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