The discussion focuses on calculating the length of a parametric path defined by the equations (2 cos t - cos 2t, 2 sin t - sin 2t) over the interval 0 ≤ t ≤ π/2. The user has derived an expression involving the antiderivative of √(1 - cos t) and reached the result of 2√2. The key transformation involves recognizing that √(1 - cos t) can be expressed as √2 sin(t/2), which simplifies the integration process necessary for finding the path length.
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stau40 said:Homework Statement
Find the length of the path over (2 cos t - cos 2t, 2 sin t - sin 2t) 0<=t<=(pi/2)
Homework Equations
sin^(2) x = (1-cos 2x)/2
The Attempt at a Solution
I have worked my way thru the problem and I have arrived at 2 (sq root 2) antiderivative (sq root (1-cos t)), but I'm not sure how this coverts into the relevant equation above? Thanks in advance!