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How to find the magnetic flux thru a bent loop with given angle

  1. Apr 21, 2010 #1
    1. The problem statement, all variables and given/known data

    A 10cm x 10cm square is bent at a 90 degree angle. A uniform 0.050T magnetic field points downward at 45 degree angle. What is the magnetic flux through the loop?

    http://i134.photobucket.com/albums/q113/duckman_011/Image.jpg" [Broken]

    2. Relevant equations

    Magnetic Flux= Area of eff *B ( Magnetic Field).
    Magnetic Flux= A eff*B*cos(theta).


    3. The attempt at a solution

    Given:
    B ( Magnetic Field) = 0.050 Tesla
    Angle of 45 degree of the bent loop
    Area = 10cm x 10cm

    Magnetic Flux= A eff*B*cos(theta).

    (0.10 cm * 0.10 cm) * 0.050 T * cos 45 degree = 3.535 e -4 Wb


    Im not sure if that is correct. Although the problem gives us a area of 10cm x 10cm it seems to easy to just treat 10cm x 10cm as as the area of effected?

    Do I need to incorporate 5cm for the base and 10 cm for the height?
    If I do I have

    (.5cm * .10cm)^2 * 0.050 * cos 45 degree = .0025 *0.050 * cos 45 degrees = 8.838e-5

    I doubled .5cm * .10cm cause there is a left and right
     
    Last edited by a moderator: May 4, 2017
  2. jcsd
  3. Apr 21, 2010 #2
    nm I got it
     
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