How to find the maximum voltage that can be placed across a capacitor.

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SUMMARY

The maximum voltage that can be applied across a parallel plate strontium titanate filled capacitor is determined by its dielectric strength. Given the dielectric strength of 8.0 kV/mm, the maximum voltage can be calculated by multiplying this value by the separation distance of the plates, which is 0.070 mm. This results in a maximum voltage of 0.56 kV, or 560 V. The capacitance of the capacitor is 30.570 µF, which is relevant for understanding its energy storage capacity but does not affect the maximum voltage directly.

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  • Understanding of capacitor fundamentals
  • Knowledge of dielectric materials and their properties
  • Familiarity with the concept of dielectric strength
  • Basic skills in unit conversion and calculations
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  • Learn about the calculation of capacitance in different capacitor configurations
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Electrical engineers, physics students, and anyone involved in capacitor design and analysis will benefit from this discussion.

squintyeyes
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How do you find the maximum voltage that can be placed across the capacitor?

It is a parallel plate strontium titanate filled capacitor, that has plates of area 0.78 m^2 and a separation of 0.070 mm. It also has a dielectric constant of 310 and a dielectric strength of 8.0 kV/mm.

I already figured out that the capacitance is 30.570 * 10^-6 F

But i can't seem to figure out how to find the max voltage.
 
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squintyeyes said:
How do you find the maximum voltage that can be placed across the capacitor?

It is a parallel plate strontium titanate filled capacitor, that has plates of area 0.78 m^2 and a separation of 0.070 mm. It also has a dielectric constant of 310 and a dielectric strength of 8.0 kV/mm.

I already figured out that the capacitance is 30.570 * 10^-6 F

But i can't seem to figure out how to find the max voltage.

The dielectric strength gives you the answer.Look at the units.What do they tell you?
 
thanks!
 

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