How to Find the 't' Value in Integral Calculus?

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temp
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hello
commonly we have:
[tex]\int^t_0 \ dx=M[/tex]

"M" is a specific number (the result of integal)

my question:
having value of "M", how we can find the "t" value
 
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temp said:
hello
commonly we have:
[tex]\int^t_0 \ dx=M[/tex]

"M" is a specific number (the result of integal)

my question:
having value of "M", how we can find the "t" value

This sounds much like homework to me. >"<

What have you done? Have you tried anything?

Ok, I'll give you some hints then:

1. What is the anti-derivative of: [tex]\int dx = ?[/tex]

2. What is : [tex]\int_0 ^ t dx = ?[/tex] in terms of t?

3. What is the relation between t, and M?
 
temp said:
hello
commonly we have:
[tex]\int^t_0 \ dx=M[/tex]

"M" is a specific number (the result of integal)

my question:
having value of "M", how we can find the "t" value

In case this isn't homework and is a question from curiosity: In general, there is a function being integrated; [tex]\int^t_0 f(x) dx=M[/tex]. In which case, the answer to your question is "only if we know the function, f."
 
i know the function f(x)
suppose that f(x) is x

[tex]\int^t_0 x dx=M[/tex]
 
What IS the integral (anti-derivative) of x? Do the integration on the left, set it equal to M and solve the equation for t.

In the very simple case, you started with, [itex]\int_0^t dx[/itex], the anti-derivative of the constant 1 is just x
[tex]\int_0^t dx= x\right|_0^t= t[/itex]<br /> In that case, whatever number M is, you have t= M. For the case of <br /> [tex]\int_0^t x dx= M[/tex]<br /> it is almost as simple.[/tex]