How to Find the Total Distance Traveled from 0 to 10 Seconds?

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To find the total distance traveled by a particle from 0 to 10 seconds, the displacement equation s=0.7t^2-0.1t^3+0.5t is used. The distance from 0 to 5 seconds is calculated as 7.5 meters, but there is confusion about the distance from 5 to 10 seconds. It is clarified that knowing when the displacement is zero is crucial because the displacement can become negative after that point, affecting the total distance calculation. The correct approach involves summing the absolute values of the displacements at the relevant time intervals to avoid negative values. Ultimately, the total distance traveled is confirmed to be 40 meters.
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Homework Statement


the following is a equation to find the displacement of a particle. I've found it is instantaneous at rest at t=5. now need to find the distance traveled between 0 to 10s.

i found distance traveling between 0 to 5 s is 7.5

but no idea how to find distance traveled between 5 to 10s...please help.

Homework Equations



s=0.7t^2-0.1t^3+0.5t

The Attempt at a Solution



32.5m
 
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You don't need to know when the velocity is zero to solve this, you need to know at what time T the displacement is zero. Then the total distance traveled is |s(T)-s(0)|+|s(10)-s(T)|.
 
yes i use|s(5)-s(0)|+|s(10)-s(5)| = 7.5+32.5=40but the ans is 40 instead of 32.5
 
That's no good. The displacement isn't zero when t=5.
 
thanks i got the ans but i wonder why we have to know what time the displacement is zero??i can't get it~.~
 
You need to know when the displacement is zero because after that time the displacement becomes negative (and distance is never negative).
 
i get it but i wonder can i do it with find t when v=0? because your method seem not suitable for finding distance between t and t1(where t and t1 are the time when s=0)

can you please point out my mistake in the following equation?

|s(5)-s(0)|+|s(10)-s(5)| = 7.5+32.5=40

thanks a lot:)
 
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