How to Find v1 and v2 Using Nodal Analysis?

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SUMMARY

The discussion focuses on finding voltages v1 and v2 using nodal analysis, specifically addressing the application of Kirchhoff's Current Law (KCL) instead of source transformation. The user initially calculated v1 as -145/8 and v2 as 5/2, but confusion arose regarding the correct methodology. Participants emphasized the importance of showing work and using KCL equations for the two nodes to arrive at the correct solution, rather than relying on source transformations.

PREREQUISITES
  • Understanding of Kirchhoff's Current Law (KCL)
  • Familiarity with nodal analysis techniques
  • Basic knowledge of electrical circuit components (voltage sources, resistors)
  • Experience with circuit analysis problems
NEXT STEPS
  • Study the application of Kirchhoff's Current Law (KCL) in circuit analysis
  • Learn the nodal analysis method for solving electrical circuits
  • Review source transformation techniques and their limitations
  • Practice solving circuit problems using KCL and nodal analysis
USEFUL FOR

Electrical engineering students, circuit designers, and anyone looking to enhance their skills in circuit analysis and problem-solving using nodal methods.

circuitaki
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hi dears,

kindly tell me the complete procedre to find out the v1 and v2
v1= -145/8

v2 = 5/2

I have tried it and I reach here

Apply Source transformation theorem.The 5A and 3ohms &2 ohms are converted into single voltage source 25V ( 5A*3+2) in series with 5ohms(3+2).But the positive terminal connected to ground pin.
Similarly 2A and 4ohms are converted into single voltage source 8V( 2A*4ohm) in series with 4 ohm resistor
hhow to go more further I am confuse and am until here am I right or wrong
 

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Your subject line says "using nodal". This problem is easy to solve using the nodal method, and you shouldn't do any source transformations.

Do you know what Kirchoff's current law (KCL) is?

What you need to do is write the KCL equations for the two nodes. If you will make an attempt to do that and show your work, then you will get some more help if you need it.
 

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