How to get from pump flow rate to pressure change

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SUMMARY

The discussion centers on determining the appropriate pump for delivering 40 gallons of water per hour to a height of 8 feet, requiring a pressure change of 3.44 psi as calculated using the Bernoulli equation. Participants emphasize the necessity of selecting a pump that can achieve at least 8 feet of head, as increasing flow rate will not compensate for inadequate head capacity. The conversation also touches on the relationship between flow rate and head height, clarifying that a pump's specifications must align with the desired operational parameters.

PREREQUISITES
  • Understanding of the Bernoulli equation
  • Knowledge of pump specifications and head capacity
  • Familiarity with fluid mechanics principles
  • Experience with flow rate calculations
NEXT STEPS
  • Research pump selection criteria for specific head and flow requirements
  • Learn about the impact of piping design on head loss
  • Investigate fluid mechanics principles related to pump performance
  • Explore product specifications for pumps with varying flow rates and head capacities
USEFUL FOR

Engineers, fluid mechanics students, and anyone involved in selecting or designing pumping systems for water delivery applications.

zzinfinity
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Hi,
Essentially what I need is a pump that will pump 40 gallons of water per hour to a height of 8 feet. Ignoring pressure losses in the lines (for now) I used the bernouli equation to determine that I need a pressure change of 3.44 psi in my pump. I found these pumps that look suitable but all list a max head far lower than the 8 feet I need. http://www.drsfostersmith.com/product/prod_display.cfm?pcatid=21414

I was thinking maybe just use one with a higher volume flow to compensate for the head loss. Maybe the 100 gph one? Is there a way to determine exactly what I need? Thanks!
 
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If the pump cannot deliver a head greater than 8', increasing the flow will not compensate. Find a pump which can deliver at least 8' of head, or re-design the piping system to reduce the head loss.
 
Fascinating. Fluid mechanics has always baffled me. Thanks!
 
Out of curiosity, is there a fundamental reason why a pump that can pump 200 gph to a height of 5 feet, can't also pump 100 gph to a height of 10 feet?
 

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