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^{2}-dv

^{2}) (without a dv after it), with c a real positive constant larger than the upper limit of the integral, how can I get it into the usual form of an integral f(v) dv ?

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In summary, the conversation discusses the process of integrating 1/sqrt(c2-dv2) from first principles in the context of special relativity and Lorentz transformations. The speaker is attempting to manipulate the integral to get it into the usual form of an integral f(v) dv, but is unsure how to do so.

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[tex]\int \frac{1}{\sqrt{c^2- dv^2}}[/tex]

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The limits of integration for an integral can be determined by looking at the given function and identifying the values that the variable can take. These values will then become the lower and upper limits of integration.

Yes, the order of integration can be changed for a double or triple integral as long as the limits of integration are adjusted accordingly to match the new order.

Converting an integral into standard form allows for easier evaluation and comparison with other integrals. It also helps to identify patterns and relationships among different integrals.

Yes, there are various techniques such as substitution, integration by parts, and using special trigonometric identities that can be used to convert an integral into standard form.

No, it is not necessary to convert an integral into standard form before evaluating it. However, it can make the evaluation process easier and more efficient in some cases.

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