How to Identify a Metal Using Work Function and Wavelength?

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SUMMARY

The discussion focuses on calculating the work function of a metal using the photoelectric effect, specifically with ultraviolet radiation at a wavelength of 200.0 nm and a stopping potential of 3.33 V. The key formula involved is the photoelectric equation, which relates the energy of the incident photons to the work function and the kinetic energy of emitted electrons. Participants emphasize the importance of converting wavelength to energy using the equation E = hc/λ, where h is Planck's constant and c is the speed of light. The work function can then be determined by rearranging the equation to solve for the metal's identity.

PREREQUISITES
  • Understanding of the photoelectric effect and its equations
  • Familiarity with Planck's constant (h) and the speed of light (c)
  • Ability to convert between wavelength and energy
  • Basic knowledge of stopping potential in the context of electron emission
NEXT STEPS
  • Learn how to apply the photoelectric effect equation in various scenarios
  • Study the conversion of wavelength to energy using E = hc/λ
  • Explore different metals and their work functions for practical identification
  • Investigate the implications of stopping potential on emitted electron energy
USEFUL FOR

Students and professionals in physics, particularly those studying quantum mechanics and the photoelectric effect, as well as researchers involved in material science and metal identification.

geej77
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Calculating Work Function

I am having trouble identifying a metal (based on its work function) given the wavelength and stopping potential. I will give more specifics below but can anyone help me with useful formulas to make this a little more streamlined in the future? Thanks!

Ultraviolet radiation with wavelength 200.0 nm hits a metal and electrons are emitted, which can be stopped by a potential of 3.33 V. What is the work function/identity of the metal?
 
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Start with the equation describing photoelectric effect. You will need to convert between different ways of expressing energy, other than that it is just a simple plug and chug.
 
Thanks I will give it a shot!
 

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