How to integrate 1/(x^2 +1)^2, does partial fractions work?

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To integrate 1/(x^2 + 1)^2, partial fractions initially seem ineffective as they lead to trivial coefficients. A suggested approach is to use trigonometric substitution, specifically substituting x with tan(u), which simplifies the integration process. Additionally, employing complex linear fractions allows for manipulation into a real form by combining terms with their complex conjugates. The relationship between logarithmic and arctangent functions is crucial in this transformation. This method ultimately provides a workable solution for the integration problem.
timjones007
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how do you integrate 1/(x2 + 1)2 ?


i have tried integration by partial fractions but when you set 1 equal to (Ax +B)(x2+1) + (Cx + D) this leads to A=B=C=0 and D=1 which just gives you the original equation
 
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Try subbing x=tan(u), dx=1/cos^2(u)
 


Partial fraction in terms of the complex linear fractions 1/(x±i) and 1/(x±i)^2 will also work. You can then take together terms with their complex conjugate and then rewrite everything in a manifestly real form (you need to use the relation between the logarithm and arctan etc.).
 


ah thank you that works
 
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