How to Integrate Cotangent and Cosecant with Odd Powers?

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To integrate cot^a(x) csc^b(x) dx when both a and b are odd, start by rewriting cotangent and cosecant in terms of sine and cosine. Specifically, express cot^a(x) as cos^a(x)/sin^a(x) and csc^b(x) as 1/sin^b(x). Remove one factor each of csc(x) and cot(x), leading to an integral of cot^(a-1)(x) csc^(b-1)(x) csc(x) cot(x) dx. Utilize the identity cot^2(x) + 1 = csc^2(x) to simplify the expression, allowing for substitution with u = csc(x). This method effectively reduces the integral to a more manageable form involving powers of csc^2(x).
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Describe the method you would use to integrate

cot^a(x) csc^b(x) dx

If a and b are odd?

An explanation of the strategy would be a huge help!
 
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I would definitely try to put everything into terms of sin and cos.

cot^a(x) = Cos^a(x) / sin^a(x)

csc^b(x) = 1/sin^b(x)

this is where i would start. from there, you can sum the powers of the sin's in the denominators and try u substitution or something.
 
adelaide87 said:
Describe the method you would use to integrate

cot^a(x) csc^b(x) dx

If a and b are odd?

An explanation of the strategy would be a huge help!
Take out one factor each of csc x and cot x, leaving you with
\int cot^{a-1}(x)csc^{b - 1}(x)~csc(x)cot(x)dx

Use the identity cot2(x) + 1 = csc2(x) (or equivalently, cot2(x) = csc2(x) - 1) to replace the cota - 1 factor.

At that point you'll have a sum of terms that involve various powers of csc2(x) and you can use an ordinary substitution, with u = csc(x).
 
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