How to integrate int sin(ln(x)) ?

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Homework Help Overview

The discussion revolves around the integration of the function sin(ln(x)), specifically the integral ∫sin(ln(x)) dx. Participants are exploring methods of substitution and integration techniques within the context of calculus.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts substitution with u = ln(x) but encounters issues with the resulting expression. Some participants question how to express x in terms of u and discuss the implications of this substitution. Others suggest using integration by parts as a potential method for solving the integral.

Discussion Status

The discussion is active, with participants providing feedback on each other's attempts and clarifying concepts related to the substitution. There is a mix of correct and incorrect reasoning being explored, particularly regarding the relationship between x and u, and the application of integration techniques.

Contextual Notes

Participants are navigating through the implications of their substitutions and the properties of logarithmic and exponential functions. There is an emphasis on understanding the inverse relationships between these functions, which may be affecting their reasoning.

Shaybay92
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Homework Statement



I am having trouble solving the following:

[tex]\int[/tex]sin(lnx) dx


The Attempt at a Solution



I let u = ln x but this makes xdu = dx so I am left with

[tex]\int[/tex]x sinu du
 
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That's the substitution you want to use,but you can't leave the x in there. If u=lnx, then x is?
 


Would x = u2?

[tex]\int[/tex]ue sin u du

Then do you do it by parts or something?
 


How on Earth did you get that? Can you solve [itex]u=\ln x[/itex] for x?
 


Oops I meant e^u, is that right?
 


Yes that's correct. You can now use integration by parts, twice.
 


does e(lnx) cancel to 1?
 


No and you should really know that at this stage! If a function has an inverse, [itex]f^{-1}(x)[/itex], then [itex]f^{-1}(f(x))=f(f^{-1}(x))=x[/itex]. So what is [itex]e^{\ln x}[/itex] and [itex]\ln e^x[/itex]?
 

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