Can anyone explain this integration for me?

Rijad Hadzic
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Homework Statement


http://imgur.com/a/Y8NW0

Basically we start with a function of t, which was differentiated twice, that function = [itex]F_o / m[/itex]

Fo is a constant force, and I assume m is mass though my book doesn't state that.

Homework Equations

The Attempt at a Solution



Integrating the function, I multiply m to the other side, because I assume m is mass and mass is a constant. so it shouldn't really matter.

since F_o is a force, that means it is Kg * m/s^2, divided by mass which is in kg, you get m/s^2 which is indeed acceleration, the second derivative of time.

Integrating, I get

[itex]m\int x^{''}(t) \, dt = \int F_o \, dt[/itex]

[itex]m\int x^{''}(t) \, dt = F_o(t)[/itex]

But as you see from the link I provided, the book states
[itex]m\int x^{''}(t) \, dt = F_o(t) + V_o[/itex]

First off, I don't even know what V_o is. Is it inital velocity, or is it final velocity? It would make sense for it to be final velocity since [itex]m\int x^{''}(t) \, dt[/itex] is literally velocity itself..

I was under the impression that if you integrate something with respect to time, and that function does not have a time variable, it would simply be that function times the variable t.

Why is it that they are adding V_o in this example?
 
on Phys.org
I marked it as solved. I guess I didn't read clearly enough, V_o is the constant of integration.

That makes sense now. Always end your integrals with + C, I feel dumb now..
 

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