How to integrate this fraction function - help

[Femme_physics]

I noticed that in this case this is the answer:

http://img804.imageshack.us/img804/3513/1con.jpg But this is what I turned up with:

http://img163.imageshack.us/img163/4083/reupp.jpg

And you can add a +c to that.

What did I do wrong?

 

[Charles49]

Use power rule for integration.

 

[Pengwuino]

The 2 stays in the denominator.

$${{1}\over{2x^{7}}} = {{x^{-7}\over{2}}}$$

 

[niklaus]

1/(2x^7) = 1/2 x^-7, not 2x^-7

 

[Femme_physics]

The 2 stays in the denominator.

$${{1}\over{2x^{7}}} = {{x^{-7}\over{2}}}$$

That clears it, thanks! :)

 

[Ouabache]

Alternatively, you may pull out any constant from the integral
such that: $$\int \frac {dx}{2x^7} = \frac {1}{2} \int \frac {1}{x^7} dx = \frac {1}{2} \int x^{-7} dx$$
it makes the integration a bit easier.