- #1
Saladsamurai
- 3,020
- 7
After solving a DE by Laplace I was left with
[tex]\frac{1}{s^3}[/tex]
Now I have a formula for [tex] \frac{n!}{s^{n+1}}[/tex]
which could be [tex]\frac{2}{s^{2+1}}[/tex]
Now if I just multiply the [tex]\frac{2}{s^{2+1}}[/tex]
by a factor of 1/2, is that the same same as my original?
Sorry if this is a stupid question.
[tex]\frac{1}{s^3}[/tex]
Now I have a formula for [tex] \frac{n!}{s^{n+1}}[/tex]
which could be [tex]\frac{2}{s^{2+1}}[/tex]
Now if I just multiply the [tex]\frac{2}{s^{2+1}}[/tex]
by a factor of 1/2, is that the same same as my original?
Sorry if this is a stupid question.