Inverse Laplace Transform: How to Manipulate Fractions for Completing the Square

[TyErd]

Homework Statement

Find the inverse laplace transform of \frac{3s + 7}{s^{2} - 2s + 10}

Homework Equations

completing the square.
e^{at}sin(bt) = \frac{b}{(s-a)^{2} + b^{2}}
e^{at}cos(bt) = \frac{s-a}{(s-a)^{2} + b^{2}}

The Attempt at a Solution

F(s)= \frac{3s + 7}{s^{2} - 2s + 10}
F(s) = \frac{3s + 7}{(s-1)^{2} +9}
F(s) = \frac{3s}{(s-1)^{2} +9} + \frac{7}{(s-1)^{2} +9}

after this i don't know how to manipulate the first fraction to fit the cosine equation. I know the 3 can be taken up front and a=1 and b=3 I am pretty sure when comparing with the cosine equation but there the problem of making s into s-1.

 

[LCKurtz]

Don't you have the shifting theorems? Like$$
\mathcal L e^{at}f(t) = \mathcal L(f(t))|_{s \to s-a}$$