How to Measure Current in a Hall Bar Device Using SR830 Lock-in Amplifier?

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SUMMARY

The discussion focuses on measuring current in a Hall bar device using the SR830 Lock-In Amplifier (LIA). The SR830 features a current measurement mode, which is detailed in its user manual. Users are encouraged to clarify whether they intend to measure DC or AC magnetic fields, as this impacts the measurement approach. The proposed method involves applying a sine wave to one voltage terminal while measuring current at the gating electrode, treating the setup as a capacitor.

PREREQUISITES
  • Understanding of Hall bar devices and their operation
  • Familiarity with SR830 Lock-In Amplifier functionalities
  • Basic knowledge of AC and DC magnetic field measurements
  • Experience with circuit diagrams and electronic components
NEXT STEPS
  • Review the SR830 Lock-In Amplifier user manual for current measurement procedures
  • Study Hall effect principles and their application in sensor technology
  • Learn about AC versus DC magnetic field measurement techniques
  • Explore circuit design for measuring current in capacitive setups
USEFUL FOR

Researchers, electrical engineers, and physicists involved in experimental setups using Hall bar devices and Lock-In Amplifiers for current measurement applications.

K_c_1
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TL;DR
How can i use sr830 amplifier to measure current(I) of a hall device?
I want to measure the current of hall bar device using sr830 LIA. it is possible with sr830 to measure current but how ?
 
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Welcome to PF.

What have you found in your research on this so far? How much have you used Lock-In amplifiers in the past, and for what tasks? What does your experiment look like so far for measuring the current of your Hall sensor (versus magnetic field?)?
 
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The SR 830 has a current measurement mode shown in the user manual. However, most Hall devices provide an output voltage.
Do you want to measure a DC or AC magnetic field?
 
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Thankyou all for the reply
actually what i want to do was put sin out at one voltage terminal and A at the gating electrode, From there measure the current. basically it will be acting as a capacitor. the resistance between the voltage terminal and gate electrode is in Mohm. So by using A(Current input 10^6 or 10^8) i think it is possible but it might show overload in X and Y
 
I'm sorry but I don't understand what you want to do. Could you post a diagram?
 

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