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Homework Statement
Find the peak current in the circuit config:
V1 = 15v amplitude, 1khz freq.
R = 1.5k
Vd = 0.7v
Draw the transfer characteristic.
http://img341.imageshack.us/img341/9761/picture2ge7.jpg
Homework Equations
The Attempt at a Solution
Transfer Characteristic
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I only understand the transfer characteristic if the diode is flipped. When the diode is flipped, The source has to supply more than 0.7V to turn the diode on, then after there will be a constant voltage drop of .7v across the diode as you keep increasing the voltage.
However, in my case, I'm guessing that the voltage Vs would only turn the diode on when it is decreasing, so the cathode part of the diode is not greater than Vo?Peak Current
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KVL: -V1 - Vdiode + Vr = 0
Vr / R = (V1 + Vdiode) / R = Ir
so peak current = Ir = (V1 + Vdiode) / R
Is my derivation correct? Thankss!
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