Find the maximum voltage of an AC generator

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SUMMARY

The maximum voltage across the 30 Ω resistor in the given AC generator circuit is determined by the transformer turns ratio. With the generator having 4 loops and the resistor having 9 loops, the voltage across the resistor can be calculated using the formula V = (N_secondary/N_primary) * V_primary. The peak power dissipated in the resistor can be calculated using the formula P_diss = I^2/R, where I is the current derived from the maximum voltage. The sinusoidal voltage output oscillates between 500 V and -500 V, establishing the peak voltage for calculations.

PREREQUISITES
  • Understanding of AC circuit theory
  • Familiarity with transformer principles
  • Knowledge of Ohm's Law (V=IR)
  • Ability to calculate power dissipation (P=IV or P=I^2/R)
NEXT STEPS
  • Calculate the transformer turns ratio for the given circuit
  • Learn about the relationship between voltage and current in transformers
  • Explore the concept of peak power in resistive loads
  • Study the implications of sinusoidal waveforms in AC circuits
USEFUL FOR

Electrical engineering students, circuit designers, and anyone involved in AC circuit analysis and transformer applications.

Jack01236
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Homework Statement


The sinusoidal voltage output from the AC generator oscillates between 500 V and -500 V. The circuit for an ideal transformer is constructed with a generator, transformer and a 30 Ω resistor . The generator makes 4 loops with the transformer and the resistor makes 9 loops with the transformer (the figure does not show these loops accurately). What is the maximum voltage across the resistor R ?

What is the peak or maximum power dissipated in R?



Homework Equations



V=IR B=unI Pdiss = I^2/R or P=IV

The Attempt at a Solution


I've attempted to find the current first, given that V is 500 V and R is 30 ohms, however I'm not sure this is the correct current value to use. Is the correct number of turns equal to 13, or is it just 9? Once I have the correct I value, I can use this to find part 1, then use that answer to find part 2.
 

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Jack01236 said:

Homework Statement


The sinusoidal voltage output from the AC generator oscillates between 500 V and -500 V. The circuit for an ideal transformer is constructed with a generator, transformer and a 30 Ω resistor . The generator makes 4 loops with the transformer and the resistor makes 9 loops with the transformer (the figure does not show these loops accurately). What is the maximum voltage across the resistor R ?

What is the peak or maximum power dissipated in R?

Homework Equations



V=IR B=unI Pdiss = I^2/R or P=IV

The Attempt at a Solution


I've attempted to find the current first, given that V is 500 V and R is 30 ohms, however I'm not sure this is the correct current value to use. Is the correct number of turns equal to 13, or is it just 9? Once I have the correct I value, I can use this to find part 1, then use that answer to find part 2.
Transformers have two sets of coils: the primary set and the secondary set.

What's the purpose of putting a transformer in an AC circuit?

http://hyperphysics.phy-astr.gsu.edu/hbase/magnetic/transf.html
 

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