Piecewise Linear Modeling (diode)

Click For Summary

Discussion Overview

The discussion revolves around the use of piecewise linear modeling to estimate the voltage across a pn junction diode connected to a Thevenin circuit with a square wave input. Participants explore the diode's behavior at low (0V) and high (1V) states of the voltage source, considering the diode's turn-on voltage and small current approximations.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Technical explanation

Main Points Raised

  • One participant proposes using a diode turn-on voltage of 0.7V and suggests an initial current of 1mA to calculate the dynamic resistance (rd) as 40Ω.
  • Another participant introduces a graphical method to find the operating point by plotting the voltage source/resistor and the diode characteristics, indicating that the intersection gives the solution.
  • A later reply questions the choice of 1mA for the diode current, suggesting that a more logical choice would be needed given the input voltage of 1V.
  • Following this, a participant calculates the diode current (iD) to be 0.3mA and updates the dynamic resistance to approximately 83Ω, leading to a calculated diode voltage of 725mV when the voltage source is 1V.
  • Another participant confirms the piecewise-linear approximation, describing it as a straight line along the V axis up to 0.7V and then a line with a slope of 1/rd up to the operating point.

Areas of Agreement / Disagreement

Participants express differing views on the appropriate choice of diode current and the implications for the dynamic resistance. There is no consensus on the best approach, and the discussion remains exploratory with multiple perspectives on the modeling process.

Contextual Notes

Participants do not fully resolve the assumptions regarding the choice of current or the implications of the piecewise linear model, leaving some mathematical steps and definitions open to interpretation.

hogrampage
Messages
107
Reaction score
1

Homework Statement


A pn junction diode is connected to a Thevenin circuit consisting of a 0-to-1V, 1kHz square wave and 1kΩ resistor. Use piecewise linear modeling to estimate the diode voltage for the low (0V), and high (1V) states of the voltage source. Assume the diode to have an approximate turn-on voltage of 0.7V for small currents.


Homework Equations


rd = \frac{nV_{T}}{I_{D}}
iD = \frac{V_{th}-V_{f}}{R_{th}+r_{d}}
VD = Vf + iDrd


The Attempt at a Solution


I was thinking of just picking ID = 1mA, n = 1, and VT = 25mV so that:

rd = 40Ω

I don't know if I'm going about this right, or even where to go next.
 
Physics news on Phys.org
For the 1V case...

Are you familiar with the graphical method of finding the operating point? Plot a graph with two "curves" on it:

First one for the voltage source/resistor: Plot open circuit voltage, short circuit current and join with straight line.

Another for the diode, in particular the equation VD = iDrd + Vf is of the form y = mx + c ... a straight line.

Where they cross is your answer.
 
hogrampage said:

Homework Statement


A pn junction diode is connected to a Thevenin circuit consisting of a 0-to-1V, 1kHz square wave and 1kΩ resistor. Use piecewise linear modeling to estimate the diode voltage for the low (0V), and high (1V) states of the voltage source. Assume the diode to have an approximate turn-on voltage of 0.7V for small currents.

The Attempt at a Solution


I was thinking of just picking ID = 1mA, n = 1, and VT = 25mV so that:

rd = 40Ω

I don't know if I'm going about this right, or even where to go next.

Picking iD = 1 mA is definitely not a good idea.

You know VD will be close to 0.7V. So what is a logical choice for iD if the input to the 1K resistor is 1V?
 
With that info, I found iD to be 0.3mA. Then, rd is ~83Ω with n=1 and VT=25mV. So, when the voltage source is 1V:

VD=0.7+(0.0003)(83)=725mV
 
Assuming the piecewise-linear approximation they have in mind is a straight line along the V axis (iD=0) up to V = 0.7V and then a straight line of slope 1/rd up to the operating point iD ~ 0.3 mA, then that would be correct.
 
Alright, thanks :D.
 

Similar threads

Replies
0
Views
2K
Replies
3
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 1 ·
Replies
1
Views
6K
  • · Replies 59 ·
2
Replies
59
Views
7K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
14K
  • · Replies 1 ·
Replies
1
Views
4K