How to Multiply by a Conjugate with Multiple Terms?

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To multiply by a conjugate with multiple terms, focus on simplifying the expression by identifying the conjugate of the relevant terms. In the given limit problem, the expression involves two square root terms, which can be addressed by multiplying the numerator and denominator by the conjugate of the square root terms. This approach helps eliminate the square roots and simplifies the limit calculation. The discussion highlights confusion around the limit evaluation, particularly regarding how to handle the terms effectively. Understanding the multiplication of conjugates is crucial for simplifying complex expressions in calculus.
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multiplying by a conjugate??

Homework Statement



I am dealing with a limit, however, I am not sure how to multiply by a conjugate when there are two variables and three terms on top. For example

lim [3h + sqrt( 2x +2h) - sqrt( 2x)] / h
h->0


i don't need help solving it, i just need to know how would we multiply it by a conjugate when there are more than 2 terms?
 
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I don't know how you got that but lim h->0 3h/h=3. There. Now you only have two terms in the numerator.
 


how did you get h=3?, I tried the problem as well and got stuck.
 


cam875 said:
how did you get h=3?, I tried the problem as well and got stuck.

I didn't get h=3. I got limit h->0 3h/h=3. That leaves you with figuring out limit h->0 (sqrt(2x+2h)-sqrt(2x))/h.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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