Limit definition of derivative problem

In summary, the conversation discusses using the definition of derivative to find f'(x) for f(x) = x - sqrt(x). The author solves the problem by multiplying by the conjugate and taking the limit as h approaches 0. The author's friend suggests there may be other ways to solve the problem. The author also asks about the result of using the limit definition of derivative for f(x) = sqrt(x) and a = 0. The respondent clarifies that the ratio does not give 0 and mentions general rules for obtaining the derivative of powers. The author then realizes their mistake.
  • #1
physicsernaw
41
0

Homework Statement



Using the definition of derivative find f'(x) for f(x) = x - sqrt(x)

Homework Equations



None.

The Attempt at a Solution



lim h --> 0 : ((x + h) - sqrt(x + h) - x + sqrt(x))/h

1 - (sqrt(x + h) - sqrt(x))/h

Multiply by conjugate..

1 - h/(h*(sqrt(x) + sqrt(x+h)))

1 - 1/(sqrt(x+h) + sqrt(x))

lim as h --> 0 makes it: 1 - 1/2sqrt(x)

-------------------------------------------------------
QUESTION:

My question is, is there a way to solve this problem without multiplying by the conjugate? My friend says there's more ways but I don't see how?

Also, how come using the limit definition of derivative with
(f(x) - f(a)) / (x - a) yields zero?
 
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  • #2
physicsernaw said:

Homework Statement



Using the definition of derivative find f'(x) for f(x) = x - sqrt(x)

Homework Equations



None.

The Attempt at a Solution



lim h --> 0 : ((x + h) - sqrt(x + h) - x + sqrt(x))/h

1 - (sqrt(x + h) - sqrt(x))/h

Multiply by conjugate..

1 - h/(h*(sqrt(x) + sqrt(x+h)))

1 - 1/(sqrt(x+h) + sqrt(x))

lim as h --> 0 makes it: 1 - 1/2sqrt(x)

-------------------------------------------------------
QUESTION:

My question is, is there a way to solve this problem without multiplying by the conjugate? My friend says there's more ways but I don't see how?

Also, how come using the limit definition of derivative with
(f(x) - f(a)) / (x - a) yields zero?

There are general rules for obtaining the derivative of powers like f(x) = x^k (k = any number, positive or negative).

RE: your second question: the ratio you write does NOT give 0. After all, you just finished finding the result for f(x) = sqrt(x) and a = 0: you did not get zero then, did you?
 
  • #3
Ray Vickson said:
There are general rules for obtaining the derivative of powers like f(x) = x^k (k = any number, positive or negative).

RE: your second question: the ratio you write does NOT give 0. After all, you just finished finding the result for f(x) = sqrt(x) and a = 0: you did not get zero then, did you?

I got it, was making a silly error :biggrin:
 
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