How to Normalize a Wave Function in a Potential Well?

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Homework Help Overview

The discussion revolves around normalizing a wave function defined in a one-dimensional potential well, specifically for a proton. The wave function is given as Ae^(ikx)*cos(πx/L) within the bounds of -L/2 to L/2, and the problem involves determining the probability of finding the proton between x = -L/4 and x = L/4.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to clarify the bounds for normalization, questioning whether to use -L/2 to L/2 or -L/4 to L/4. Some participants discuss the implications of integrating over the entire space versus the region where the wave function is non-zero.

Discussion Status

Participants have provided clarifications regarding the normalization process, with one confirming the appropriate bounds for integration. The original poster has recalculated the normalization constant and is considering the next steps for finding the probability, indicating a progression in the discussion.

Contextual Notes

There is an acknowledgment that normalization in one dimension typically involves integrating over all space, but practical considerations lead to focusing on the region where the wave function is non-zero.

Safder Aree
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Homework Statement


I have the wave function Ae^(ikx)*cos(pix/L) defined at -L/2 <= x <= L/2. and 0 for all other x.

The question is:
A proton is in a time-independent one-dimensional potential well.What is the probability that the proton is located between x = − L/4 and x = L/4 ?

Homework Equations


∫ψψ* = 1

The Attempt at a Solution


I know i have to normalize this first. Should I be normalizing with the bounds being -L/2 and L/2 or should the bounds be -L/4 and L/4.
A^2∫cos^2(πx/L)dx =1
(1/2)A^2[x+ L/2π (sin(2πx/L)] evaluated at some bounds.

I actually evaluated it both ways one answer gives me A=√2/L at L/2,-L/2 and the other one gives me A = √2
π/L which makes more sense (at -L/4,L/4)

But i just want to make sure i am approaching this right way.
Thank you.
 
Last edited:
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Actually, the normalization in one dimension is formally over all space, i.e. from -∞ to +∞, but since the wavefunction is zero outside the box, you would be adding a whole bunch for zeroes if you went outside it. Therefore it suffices to integrate from -L/2 to +L/2, i.e. over all space where there is non-zero probability.
 
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I actually re did it and got A=√2/L. Thank you for the clarification. Now to find the probability I can just integrate over the other bounds right?
 
Last edited:
Right. Make sure the number you get is less than 1.
 
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