How to Obtain a Magnification of -2 from a Convex Lens?

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Homework Help Overview

The discussion revolves around obtaining a magnification of -2 using a convex lens with a specified focal length. Participants explore the relationship between object distance, image distance, and focal length in the context of lens optics.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss various options for object placement relative to the lens to achieve the desired magnification. Some question how to incorporate the focal length into their reasoning, while others suggest eliminating options based on the nature of the images produced (real vs. virtual).

Discussion Status

The discussion includes attempts to clarify the conditions under which a convex lens produces a magnification of -2. Some participants have provided guidance on how to approach the problem by considering the characteristics of real and virtual objects, but there is no explicit consensus on the correct option yet.

Contextual Notes

There is a noted confusion regarding the sign of the focal length and its implications for the object distance and image distance relationships. Participants are working within the constraints of the problem statement and the properties of convex lenses.

Sylvia
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Homework Statement


You wish to obtain a magnification of -2 from a convex lens of focal length f. The only possible solution is to:

A) place a virtual object at a distance 2f/3 from the lens.
B) place a virtual object at a distance 5f/3 from the lens.
C) place a real object at a distance 3f/2 from the lens.
D) place a real object at a distance 2f/3 from the lens.
E) place a virtual object at a distance 3f/2 from the lens.

Homework Equations


(1/do) + (1/di) = (1/f)
m = -di/do
f is negative because it is a convex lens

The Attempt at a Solution


I'm not sure how to factor in focal length, I am unsure how to get the relationship between object distance and focal length
 
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Sylvia, you can attempt this quetion by eliminating approach.
Here's what you should consider,
First try by using real objects.
Note that for magnification of -2 you should have an inverted image.
We kniw for object between f and o , the image is virtual and erect hence,
Option D is ruled out.
Now considering option C
The objet will be between f and 2f
Hence image will be real and enlarged.
And also by putting magnification ( -v/u = -2) you can get your answer.
Hence option C seems correct to me.

If you want further solution letme know.
 
Sylvia said:

Homework Equations


(1/do) + (1/di) = (1/f)
m = -di/do
f is negative because it is a convex lens

The Attempt at a Solution


I'm not sure how to factor in focal length, I am unsure how to get the relationship between object distance and focal length

The focal length of convex lenses is positive.
You know how magnification defined. So you can express do in terms of di and substitute into the equation (1/do) + (1/di) = (1/f). Solve for do in terms of f.
 
Thank you both very much, I understand it now!
 
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