How to Parse an Integer in MIPS?

[iamhumble]

I am taking a MIPS class this semester and for some reason I am having a tough time parsing out an integer. Can someone give me a hint what I am doing incorrectly here? Below, I am attempting to parse the "7" and "2" out that are currently stored in register $t1. The reason for this is I later on need to compare the "7" and "2" against another number. Thanks.

# UNTITLED PROGRAM
    .data   # Data declaration section

    .text

main:      # Start of code section
           li $t1, 7214
           move $a0, $t1
           li $v0,1
exit:
           li $v0, 10
           syscall
# END OF PROGRAM

 

[Mark44]

I am taking a MIPS class this semester and for some reason I am having a tough time parsing out an integer. Can someone give me a hint what I am doing incorrectly here? Below, I am attempting to parse the "7" and "2" out that are currently stored in register $t1. The reason for this is I later on need to compare the "7" and "2" against another number. Thanks.

# UNTITLED PROGRAM
    .data   # Data declaration section

    .text

main:      # Start of code section
           li $t1, 7214
           move $a0, $t1
           li $v0,1
exit:
           li $v0, 10
           syscall
# END OF PROGRAM

Maybe you're having difficulty because neither 7 nor 2 are stored in register $t1. What's actually stored in $t1 is the bit pattern for 7124, which is 0000 0000 0000 0000 0001 1011 1101 0100₂, or 0x00001BD4 in base-16 or hexidecimal.

To get the digits out of a decimal (base-10) number, you would have to have a loop that divided the number by 10 each iteration, and kept track of the remainder. The problem as described here is pretty vague, so I can't give any more advice than that.