How to prove a wave is travelling ?

  • Thread starter Thread starter i_hate_math
  • Start date Start date
  • Tags Tags
    Wave
Click For Summary
To prove that the wave equation f(x,t)=A•sin(k•x-ω•t) represents a traveling wave, one can analyze the argument of the sine function. By setting the phase equal to a constant C, the location x can be expressed as a linear function of time t, indicating that a specific point on the waveform moves over time. The wave travels to the right if the form is kx-ωt and to the left if it is kx+ωt, with a speed given by v=ω/k. This algebraic approach confirms that the function satisfies the one-dimensional wave equation, thus establishing it as a traveling wave. Understanding this concept requires some knowledge of differential calculus.
i_hate_math
Messages
150
Reaction score
2

Homework Statement


This is not a homework of any form, I am simply interested in proving a wave equation of the form f(x,t)=A•sin(k•x-ω•t) is a traveling wave, preferably an algebraic proof. Thanks heaps!

Homework Equations


f(x,t)=A•sin(k•x-ω•t)

The Attempt at a Solution


I was able to proof this by using graphs, but I need to know the algebra behind it.
 
Physics news on Phys.org
Think of the wave as a 'waveform' (which is a fixed shape) that is traveling left or right.

Write an equation for the location of a particular point in the waveform, as a function of time.
A point in the waveform is uniquely determined by the argument to the sine function. So to fix the point in the waveform, set the phase equal to any constant C. So you have ##C=kx-\omega t##. Now solve for location ##x## as a function of ##t##. That tells you that the location of that point in the waveform is a linear function of time. It's easiest to visualise this if the point is a crest or a trough, where C is ##(2m+\frac12)\pi## or ##(2m-\frac12)\pi## respectively (##m## being an integer). But it's just as true for any point on the waveform.
 
Here's something to get you started. Look at the wave at a single point (for simplicity, look at a zero of the function). What can you deduce about the argument of the sine function? What does this tell you about the motion of the wave?

EDIT. Just got beat to it :frown:
 
To be a more accurate what you have here is a function ##f(x,t)## that satisfies the one dimensional wave equation https://en.wikipedia.org/wiki/Wave_equation

Any function that satisfies the wave equation is a traveling wave. (or in some cases a standing wave).

PS. You ll need to know a bit of differential calculus to understand the Wikipedia article.
 
Last edited:
i_hate_math said:

Homework Statement


This is not a homework of any form, I am simply interested in proving a wave equation of the form f(x,t)=A•sin(k•x-ω•t) is a traveling wave, preferably an algebraic proof. Thanks heaps!

Homework Equations


f(x,t)=A•sin(k•x-ω•t)

The Attempt at a Solution


I was able to proof this by using graphs, but I need to know the algebra behind it.
I guess we are talking about waves traveling without changing shape (otherwise we have to discuss dispersion, group velocity vs phase velocity, etc).

In general, if you have a function of the combination ##kx- \omega t## or of ##kx+ \omega t##, then you have a wave traveling to the right (or to the left in the second case) at a speed equal to ##v=\omega/k##. In other words, you can tell by using the following trick: if you set ##kx=\omega t## in the function and magically all dependence on x and t disappears, you have a wave traveling to the right without changing shape. If you set ##kx=-\omega t## in the function and magically all dependence on x and t disappears, you have a wave traveling to the left without changing shape.
 
Thread 'Correct statement about size of wire to produce larger extension'
The answer is (B) but I don't really understand why. Based on formula of Young Modulus: $$x=\frac{FL}{AE}$$ The second wire made of the same material so it means they have same Young Modulus. Larger extension means larger value of ##x## so to get larger value of ##x## we can increase ##F## and ##L## and decrease ##A## I am not sure whether there is change in ##F## for first and second wire so I will just assume ##F## does not change. It leaves (B) and (C) as possible options so why is (C)...

Similar threads

Replies
27
Views
3K
  • · Replies 5 ·
Replies
5
Views
4K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 12 ·
Replies
12
Views
4K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
8
Views
1K