How to Prove that A*B= |A||B|cos theta

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SUMMARY

The proof that A*B = |A||B|cos(theta) is established through the application of the Law of Cosines and properties of the dot product. By substituting the dot product definitions into the Law of Cosines, the equation simplifies to show that the inner product of vectors A and B is equal to the product of their magnitudes and the cosine of the angle between them. The proof confirms the commutative and distributive properties of the inner product, leading to the conclusion that a*b = |A||B|cos(theta).

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Homework Statement


Prove that A*B = |A||B|cos theta


Homework Equations


Law of cosines: c^2= a^2 + b^2 - 2abcostheta
Property of a dot product; x*x=x^2
Replace c^2, a^2, and b^2 with dot product

The Attempt at a Solution



c*c=a*a+b*b-2abcostheta
since c=a-b
c*c= (a-b) * (a-b)
c*c= (a*a-2a*b+b*b)

therefore
(a*a-2a*b+b*b) = a*a+b*b-2abcostheta
-2a*b=-2abcostheta
a*b=abcostheta


Does this look right?
 
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It looks right to me. If you need to refer to all the rules you apply in each step of your proof, you should probably notice that you utilized that the inner product is commutative and distributive.
 

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