- #1
p6.626x1034js
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hi, it's my first post :)
this is not really a homework problem but it's almost like that so...
in the xy-plane, suppose that there is a non-uniform charge density distribution between x=0 and x=d. the distribution is dependent only on x so that for any vertical line x = a (0≤a≤d), the charge density anywhere on that line is the same. for x<0 and x>d, the charge density is 0.
i would like to show that the magnitude of the electric fields at any point (x,y) where x< 0 and at any point (x,y) where x> d are the same.
I can show that the field strength in both areas are constant.
if I "zoom out" far enough , the area between x = 0 and x =d would appear like a line charge with constant linear charge density. by symmetry, i then argue that the field strength m units to the left of that line charge is equal to the field strength m units to the right of the line charge.
because the field in both areas are constant, they must be equal
is my solution valid? if it were, is there any other more "mathematical" solution?
this is not really a homework problem but it's almost like that so...
Homework Statement
in the xy-plane, suppose that there is a non-uniform charge density distribution between x=0 and x=d. the distribution is dependent only on x so that for any vertical line x = a (0≤a≤d), the charge density anywhere on that line is the same. for x<0 and x>d, the charge density is 0.
i would like to show that the magnitude of the electric fields at any point (x,y) where x< 0 and at any point (x,y) where x> d are the same.
The Attempt at a Solution
I can show that the field strength in both areas are constant.
if I "zoom out" far enough , the area between x = 0 and x =d would appear like a line charge with constant linear charge density. by symmetry, i then argue that the field strength m units to the left of that line charge is equal to the field strength m units to the right of the line charge.
because the field in both areas are constant, they must be equal
is my solution valid? if it were, is there any other more "mathematical" solution?