How to prove that the L2 norm is a non-increasing function of time?

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Homework Help Overview

The discussion revolves around proving that the L2 norm is a non-increasing function of time, which falls under the subject area of functional analysis or differential equations.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss starting points for the proof, including the potential use of the Poincare inequality and the justification for manipulating integrals. There are attempts to apply integration by parts and differential equations to analyze the behavior of the L2 norm.

Discussion Status

Some participants have provided guidance on how to approach the proof, suggesting specific mathematical techniques and manipulations. Multiple lines of reasoning are being explored, but there is no explicit consensus on a single method or solution yet.

Contextual Notes

There is mention of variable changes and integration by parts, indicating that participants are working within the constraints of mathematical rigor and notation conventions. The original poster expresses uncertainty about how to begin the proof, highlighting the exploratory nature of the discussion.

Su3liminal
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Homework Statement


image.jpg



Homework Equations


How can I start the proof? Shall I use the Poincare inequality?

The Attempt at a Solution


Well, I know that this norm is defined by
wmfWa.gif
p4kUw.gif
, but still I don't know how to start constructing the proof?
 
Last edited:
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Su3liminal said:

Homework Statement


image.jpg



Homework Equations


How can I start the proof? Shall I use the Poincare inequality?

The Attempt at a Solution


Well, I know that this norm is defined by
wmfWa.gif
p4kUw.gif
, but still I don't know how to start constructing the proof?

Start by omitting the square root. Take ##\partial / \partial t## inside the integral sign (justify!), then use the DE to eliminate, or at least, modify ##\partial{u^2}/\partial t##.
 
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Ray Vickson said:
Start by omitting the square root. Take ##\partial / \partial t## inside the integral sign (justify!), then use the DE to eliminate, or at least, modify ##\partial{u^2}/\partial t##.

Thanks! I have done what you said (note that I just made a change in variables so I stick to the symbol convention of integration by parts.):

\\2\int_{0}^{L}\frac{\partial^2 s}{\partial x^2}s dx<br /> \\<br /> \\<br /> \\u=s, dv=\frac{\partial^2 s}{\partial x^2}dx<br /> \\du=\frac{\partial s}{\partial x}dx,v=\frac{\partial s}{\partial x}<br /> <br /> \\<br /> \\<br /> \\\therefore 2\int_{0}^{L}\frac{\partial^2 s}{\partial x^2}s dx=2s\frac{\partial s}{\partial x}\mid-2\int_{0}^{L}\frac{\partial s}{\partial x}\frac{\partial s}{\partial x}dx=-2\int_{0}^{L}(\frac{\partial s}{\partial x})^{2}dx

Is that sufficient?
 
Last edited:
Standard for me would be to start with ## \frac{\partial u}{\partial t}= \frac{\partial^2 u}{\partial x^2}## and multiply by ##u## then integrate over the spatial domain ##[0,L]##.
 

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