How to prove the limit of the sequence?

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SUMMARY

The discussion centers on proving the limit of the sequence defined by \( a_{n + 1} = a_n (1 - a_n) \) with the initial condition \( 0 < a_1 < 1 \). Participants establish that \( a_n \) is a monotonically decreasing sequence that converges to zero. By defining \( b_n = n a_n \), they derive the relationship \( \frac{b_{n + 1}}{n + 1} = \frac{b_n}{n}(1 - \frac{b_n}{n}) \) as a crucial step towards proving that \( \lim_{n \to \infty} n a_n = 1 \).

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Homework Statement


Assume the sequence [tex]\{ a_n \}[/tex] satisfys [tex]0 < a_1 < 1[/tex] and [tex] a_{n + 1} = a_n (1 - a_n )(n \ge 1)[/tex],prove [tex] \mathop {\lim }\limits_{n \to \infty } {\kern 1pt} {\kern 1pt} {\kern 1pt} na_n = 1[/tex]






Homework Equations





The Attempt at a Solution



a_n is a monotonicly decreasing sequence,and it is above zero,so a_n has a limit,zero.

let [tex]b_n=n*a_n[/tex] then we got [tex] \frac{{b_{n + 1} }}{{n + 1}} = \frac{{b_n }}{n}(1 - \frac{{b_n }}{n})[/tex],but I don't know how to do next.
 
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I would go about showing first that a_n is always positive and decreasing. I would then ewxamine if you b_n is an increasing or decreasing sequence. After thay I might examine the following:

[tex] |b_{n}-1)|[/tex]

to see what I could find.
 

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