- #1
kakarotyjn
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Homework Statement
Assume the sequence [tex] \{ a_n \} [/tex] satisfys [tex] 0 < a_1 < 1 [/tex] and [tex]
a_{n + 1} = a_n (1 - a_n )(n \ge 1) [/tex],prove [tex]
\mathop {\lim }\limits_{n \to \infty } {\kern 1pt} {\kern 1pt} {\kern 1pt} na_n = 1 [/tex]
Homework Equations
The Attempt at a Solution
a_n is a monotonicly decreasing sequence,and it is above zero,so a_n has a limit,zero.
let [tex] b_n=n*a_n [/tex] then we got [tex]
\frac{{b_{n + 1} }}{{n + 1}} = \frac{{b_n }}{n}(1 - \frac{{b_n }}{n}) [/tex],but I don't know how to do next.
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