kakarotyjn
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Homework Statement
Assume the sequence [tex]\{ a_n \}[/tex] satisfys [tex]0 < a_1 < 1[/tex] and [tex] a_{n + 1} = a_n (1 - a_n )(n \ge 1)[/tex],prove [tex] \mathop {\lim }\limits_{n \to \infty } {\kern 1pt} {\kern 1pt} {\kern 1pt} na_n = 1[/tex]
Homework Equations
The Attempt at a Solution
a_n is a monotonicly decreasing sequence,and it is above zero,so a_n has a limit,zero.
let [tex]b_n=n*a_n[/tex] then we got [tex] \frac{{b_{n + 1} }}{{n + 1}} = \frac{{b_n }}{n}(1 - \frac{{b_n }}{n})[/tex],but I don't know how to do next.
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