How to prove whether a function is differentiable

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haha1234
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Homework Statement



Suppose that f is differentiable at x . Prove that ƒ(x)=lim[h→0] [itex]\frac{ƒ(x+h)-ƒ(x-h)}{2h}[/itex]

Homework Equations





The Attempt at a Solution


I think that it may be proved by first principle,but I cannot rewrite the limit into the form of lim[h→0] [itex]\frac{ƒ(x+2h)-ƒ(x)}{2h}[/itex]
So how can I solve this question?
THANKS
 
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You probably mean f'(x). You can rewrite it via u = x-h.
 
haha1234 said:

Homework Statement



Suppose that f is differentiable at x . Prove that ƒ(x)=lim[h→0] [itex]\frac{ƒ(x+h)-ƒ(x-h)}{2h}[/itex]

I assume this is [itex]f'(x) = ...[/itex]

Homework Equations





The Attempt at a Solution


I think that it may be proved by first principle,but I cannot rewrite the limit into the form of lim[h→0] [itex]\frac{ƒ(x+2h)-ƒ(x)}{2h}[/itex]
So how can I solve this question?
THANKS

Use [itex]f(x+h) - f(x-h) = (f(x+h) - f(x)) + (f(x) - f(x-h))[/itex]
 
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pasmith said:
I assume this is [itex]f'(x) = ...[/itex]



Use [itex]f(x+h) - f(x-h) = (f(x+h) - f(x)) + (f(x) - f(x-h))[/itex]

Sorry,but it maybe equals to 0.:confused: