How to reduce the standard deviation to ensure 99% of rods are within tolerance?

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SUMMARY

The discussion focuses on determining the necessary reduction in standard deviation to ensure that 99% of plastic rods, cut to a nominal length of 6 inches, fall within tolerance. The current standard deviation is 0.06 inches, and the mean length is 6 inches. The user initially misinterpreted the problem but later clarified their understanding of the tolerance requirement. The correct approach involves using the cumulative distribution function (CDF) to find the appropriate standard deviation that meets the 99% criteria.

PREREQUISITES
  • Understanding of normal distribution and its properties
  • Familiarity with standard deviation and mean calculations
  • Knowledge of cumulative distribution functions (CDF)
  • Basic statistical concepts related to tolerance intervals
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  • Calculate the required standard deviation for a normal distribution to achieve a 99% confidence interval
  • Explore the use of statistical software for calculating tolerance intervals
  • Learn about the implications of reducing standard deviation on manufacturing processes
  • Study the relationship between sample size and standard deviation in quality control
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Homework Statement


Plastic rods are cut into nominal length of 6 inches. Actual lengths are normally distributed about a mean of 6 inches and their standard deviation is 0.06 inch.

Question: To what value does the standard deviation need to be reduced if 99% of the rods must be within tolerance?

Homework Equations


sd=standard deviation
u=mean
P(a<X<=b)=F((b-u)/(sd))-F((a-u)/(sd))

The Attempt at a Solution


since they want the possibility of rods to be between u+sd and u-sd to be 0.99, b=u+sd and a=u-sd
and the equation will become
P(a<X<=b)=F((u+sd-u)/(sd))-F((u-sd-u)/(sd))
F(1)-F(-1) doesn't equal to 0.99.

Am I misinterpreting the word tolerance?
I don't know what else to try... please help thank you!
 
Last edited:
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nevermind i misread the problem...
 

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