1. The problem statement, all variables and given/known data Suppose that X is normally distributed with mean 95 and standard deviation 17. A. What is the probability that is greater than 126.79? B. What value of X does only the top 16% exceed? 2. Relevant equations z= (X-(mean of x))/standard deviation 3. The attempt at a solution using the equation, I found z= (126.79-95)/17=1.87 then using a statistical table, the value for P(z greater than 1.87) = 1 - P(z=1.87) = 0.0307 But this is wrong.. For B) I considered that 84% must be the value which the top 16% must exceed.. then 84% of 95 is 88.42 Also wrong (well I wasn't really too sure about part B) Any help would be appreciated!