How to see in what points the function changes

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SUMMARY

This discussion focuses on determining the points at which the function changes sign, specifically analyzing the function represented in the provided image link. The derivative of the function, f'(x), must be correctly calculated to find extreme points, with the equation y'(x) = 0 leading to x*2^(x-1) = 4. The correct derivative must be established to identify critical points, which are estimated to exist between x = -10 and x = 10. The conversation emphasizes the importance of presenting all relevant information on a single page for better accessibility.

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  • Understanding of calculus, specifically differentiation and critical points.
  • Familiarity with the power rule for derivatives.
  • Basic knowledge of function behavior and sign changes.
  • Ability to interpret graphical representations of functions.
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  • Learn how to correctly apply the power rule for derivatives in various functions.
  • Study methods for finding critical points and their implications on function behavior.
  • Explore numerical methods for approximating solutions to equations like f'(x) = 0.
  • Investigate graphical analysis techniques to visualize function behavior and sign changes.
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Students and professionals in mathematics, particularly those studying calculus, as well as educators seeking to enhance their teaching methods regarding function analysis and derivatives.

transgalactic
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in this function
http://img72.imageshack.us/img72/7038/31777281zi5.gif
its impossible to find the extreme points
y'(x)=0
x*2^(x-1)=4

how to find the points for which the function changes in sign??
 
Last edited by a moderator:
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transgalactic said:
in this function
http://img72.imageshack.us/img72/7038/31777281zi5.gif
its impossible to find the extreme points
y'(x)=0
x*2^(x-1)=4

how to find the points for which the function changes in sign??
From your notes, f(x) = 2x - 4x + 1
f'(x) is not equal to x*2^(x - 1) - 4. You are using the power rule for derivatives, but that applies only to xn.

After you find the correct derivative, set it to 0. You might need to settle for approximate values for where f'(x) = 0.

Based on the points you found, there has to be a minimum somewhere between x = -10 and x = 10.

BTW, for such a simple function, I personally would like it better if you included all of the information on one page, rather than forcing readers to open another Web page to see it.
 
Last edited by a moderator:

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