How to Simplify an Acute Angle Solution Using Algebra?

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The discussion centers on simplifying the sine of an acute angle using algebraic transformations. The user has computed sinθ as √44/(√10√6) and seeks to convert this to the textbook answer of √(11/15). Clarifications indicate that the transformation relies solely on algebraic manipulation rather than the properties of acute angles. Key algebraic rules, such as √a√b = √ab and √a/√b = √(a/b), are highlighted as essential for this simplification. Ultimately, the focus is on applying these algebraic principles to achieve the desired result.
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Homework Statement



Let u=3i+0j+k and v=i-2j+k have a common tail. Let \theta be the acite angle

between u and v. Calculus sin\theta

Homework Equations



ll u x v ll = ll u ll ll v ll sin\theta

The Attempt at a Solution



First of all, I solved the problem already. To save time, I will not show my work, but show

the answer I computed:

sin\theta = \frac{\sqrt{44}}{\sqrt{10}\sqrt{6}}

Which is equivalent to my textbook's answer:

sin\theta = \sqrt{\frac{11}{15}}

Now my question is how do I transform the answer I computed to the textbook's answer? I

am pretty sure that it has to do with the concept of acute angles. Can anyone please

explain this to me? Thanks.
 
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√a√b = √ab

√a/√b = √(a/b)
 
An acute angle is just one that is between 0 and \frac{\pi}{2}. Draw a pair of lines forming a (smallish) angle. There are two angles really formed, the obvious small one between them, and the huge one that's about 300 degrees on the other side.
 
Office_Shredder said:
An acute angle is just one that is between 0 and \frac{\pi}{2}. Draw a pair of lines forming a (smallish) angle. There are two angles really formed, the obvious small one between them, and the huge one that's about 300 degrees on the other side.

Hmmm, I see. But, I still do not know how to convert an obtuse angle to an acute angle. So

let's pretend that I have a an angle, say:

cos\theta = \frac{-10}{\sqrt{22}\sqrt{42}}.

How do I go about converting this angle into an acute angle without using a calculator?
 
number0 said:
First of all, I solved the problem already. To save time, I will not show my work, but show

the answer I computed:

sin\theta = \frac{\sqrt{44}}{\sqrt{10}\sqrt{6}}

Which is equivalent to my textbook's answer:

sin\theta = \sqrt{\frac{11}{15}}

Now my question is how do I transform the answer I computed to the textbook's answer? I

am pretty sure that it has to do with the concept of acute angles. Can anyone please

explain this to me? Thanks.
It has nothing to do with the concept of acute angles. It's just algebra. Use the rules rock.freak posted to simplify the expression.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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