How to Simplify an Acute Angle Solution Using Algebra?

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Homework Help Overview

The discussion centers on simplifying the expression for the sine of an acute angle formed between two vectors, u and v, represented in component form. The original poster presents their computed value for sinθ and seeks clarification on how to transform it into a textbook equivalent.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss algebraic simplification techniques, including properties of square roots. The original poster questions the relationship between their computed sine value and the textbook answer, expressing uncertainty about the transformation process. Another participant raises a related question about converting an obtuse angle to an acute angle without a calculator.

Discussion Status

There is an ongoing exploration of algebraic methods to simplify the sine expression. Some participants provide algebraic rules, while others express confusion about the conversion of angles. No consensus has been reached, but the discussion is actively engaging with the mathematical concepts involved.

Contextual Notes

Participants are working under the assumption that the transformation of sine values is related to the properties of acute angles, and there is a mention of avoiding calculator use in angle conversion discussions.

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Homework Statement



Let u=3i+0j+k and v=i-2j+k have a common tail. Let \theta be the acite angle

between u and v. Calculus sin\theta

Homework Equations



ll u x v ll = ll u ll ll v ll sin\theta

The Attempt at a Solution



First of all, I solved the problem already. To save time, I will not show my work, but show

the answer I computed:

sin\theta = \frac{\sqrt{44}}{\sqrt{10}\sqrt{6}}

Which is equivalent to my textbook's answer:

sin\theta = \sqrt{\frac{11}{15}}

Now my question is how do I transform the answer I computed to the textbook's answer? I

am pretty sure that it has to do with the concept of acute angles. Can anyone please

explain this to me? Thanks.
 
Last edited:
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√a√b = √ab

√a/√b = √(a/b)
 
An acute angle is just one that is between 0 and \frac{\pi}{2}. Draw a pair of lines forming a (smallish) angle. There are two angles really formed, the obvious small one between them, and the huge one that's about 300 degrees on the other side.
 
Office_Shredder said:
An acute angle is just one that is between 0 and \frac{\pi}{2}. Draw a pair of lines forming a (smallish) angle. There are two angles really formed, the obvious small one between them, and the huge one that's about 300 degrees on the other side.

Hmmm, I see. But, I still do not know how to convert an obtuse angle to an acute angle. So

let's pretend that I have a an angle, say:

cos\theta = \frac{-10}{\sqrt{22}\sqrt{42}}.

How do I go about converting this angle into an acute angle without using a calculator?
 
number0 said:
First of all, I solved the problem already. To save time, I will not show my work, but show

the answer I computed:

sin\theta = \frac{\sqrt{44}}{\sqrt{10}\sqrt{6}}

Which is equivalent to my textbook's answer:

sin\theta = \sqrt{\frac{11}{15}}

Now my question is how do I transform the answer I computed to the textbook's answer? I

am pretty sure that it has to do with the concept of acute angles. Can anyone please

explain this to me? Thanks.
It has nothing to do with the concept of acute angles. It's just algebra. Use the rules rock.freak posted to simplify the expression.
 

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