How to simplify an iterated trigonometric expression

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SUMMARY

The discussion centers on simplifying the iterated trigonometric expression ##\cos(\sin x)##. Participants conclude that simplification beyond this form is unlikely without employing advanced techniques such as the Taylor series for partial sums. Additionally, the Fourier series for both ##\cos(\cos x)## and ##\cos(\sin x)## is noted to be related to Bessel functions, which may provide further insights into the behavior of these functions. The identity ##\cos^2(\sin x) + \sin^2(\sin x) = 1## is also mentioned as a foundational relationship in trigonometry.

PREREQUISITES
  • Understanding of trigonometric functions and identities
  • Familiarity with Taylor series and Maclaurin series
  • Knowledge of Fourier series and their applications
  • Basic concepts of Bessel functions and their significance in mathematics
NEXT STEPS
  • Explore Taylor series expansions for trigonometric functions
  • Investigate the properties and applications of Bessel functions
  • Learn about Fourier series and their convergence properties
  • Study the relationship between trigonometric identities and their graphical representations
USEFUL FOR

Mathematicians, students studying calculus, and anyone interested in advanced trigonometric simplifications and series expansions.

Leo Liu
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Homework Statement
.
Relevant Equations
.
eg ##\cos (\sin x)##
Asking this question out of curiosity.
 
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Leo Liu said:
Homework Statement:: .
Relevant Equations:: .

eg ##\cos (\sin x)##
Asking this question out of curiosity.
I don't see how you're going to be able to get anything simpler than that.
 
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Typically this can only be done with the partial sums of the Taylor series of the functions. There are a variety of ways to calculate a partial sum of the composition, including matrix multiplication.
 
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If you are interested about the Fourier series of cos(cos x) or cos (sin x) I think they are related to the Bessel functions.
 
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Delta2 said:
If you are interested about the Fourier series of cos(cos x) or cos (sin x) I think they are related to the Bessel functions.
Thank you this is the best answer I got :D
 
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Or maybe you want something like :

##Cos^2(sinx)+ Sin^2(sinx)=1##

So that ##Cos(sinx)=\sqrt {1-Sin^2(sinx)}##?
 
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WWGD said:
Or maybe you want something like :

##Cos^2(sinx)+ Sin^2(sinx)=1##

So that ##Cos(sinx)=\sqrt {1-Sin^2(sinx)}##?
I thought of something like this, as well as a Taylor or Maclaurin series, but none of these seemed like they would serve to simplify the given expression.
 
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