Simplify Trigonometric Expression

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Homework Help Overview

The problem involves simplifying the trigonometric expression cscθtanθsecθ. Participants are exploring the relationships between trigonometric functions and their identities.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants are attempting to simplify the expression using trigonometric identities and are questioning the steps taken in the simplification process. There is a focus on whether certain terms can be canceled out to facilitate the simplification.

Discussion Status

The discussion is ongoing, with participants providing feedback on each other's attempts. Some guidance has been offered regarding the simplification process, particularly around canceling terms. However, there is no explicit consensus on the final form of the expression.

Contextual Notes

Participants are working within the constraints of homework rules, emphasizing the need for verification of their solutions rather than providing complete answers.

pbonnie
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Homework Statement


Simplify the following trigonometric expression:
cscθtanθsecθ


Homework Equations


tanθ = sinθ/cosθ
sin^2θ + cos^2θ = 1
cscθ = 1/sinθ
secθ = 1/cosθ
cotθ = 1/tanθ

The Attempt at a Solution


I just want to double check my solution.
cscθtanθsecθ = 1/sinθ x sinθ/cosθ x 1/cosθ
= ((sin^2θ + cos^2θ) x sinθ x 1)/sinθ x cosθ x cosθ
= sin^2θ x 1
= sin^2θ

Thank you!
 
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pbonnie said:

Homework Statement


Simplify the following trigonometric expression:
cscθtanθsecθ


Homework Equations


tanθ = sinθ/cosθ
sin^2θ + cos^2θ = 1
cscθ = 1/sinθ
secθ = 1/cosθ
cotθ = 1/tanθ

The Attempt at a Solution


I just want to double check my solution.
cscθtanθsecθ = 1/sinθ x sinθ/cosθ x 1/cosθ
You're OK to here, but not below. Why not simplify by doing some cancelling?
pbonnie said:
= ((sin^2θ + cos^2θ) x sinθ x 1)/sinθ x cosθ x cosθ
= sin^2θ x 1
= sin^2θ

Thank you!
 
pbonnie said:
cscθtanθsecθ = 1/sinθ x sinθ/cosθ x 1/cosθ
= ((sin^2θ + cos^2θ) x sinθ x 1)/sinθ x cosθ x cosθ

What you have above isn't incorrect, but it isn't helpful, either. I don't know how you got the line that follows (sin^2θ x 1) from this.
 
Hmm okay would I cancel out the sinθ in 1/sinθ x sinθ/cosθ x 1/cosθ so it simplifies to 1/cos^2θ?
 
Oh okay. Thanks :)
 

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